Dual nature of particle was-given by
Bohr theory
Thomson model
Heisenberg principle
de-Broglie equation
A golf-ball weigh 40.0 gm. If it is moving with a velocity of 20.0 ms-1, it's de-Broglie wavelength is
1.66 x 10-34 nm
8.28 x 10-32 nm
8.28 x 10-25 nm
1.66 x 10-24 nm
Which is the shortest wavelength line in the Lyman series of the hydrogen spectrum? (R= 1.097 x 10-2 nm-1)
94.21 nm
91.16 nm
911.6 nm
933.6 nm
Which of the following order of ionisation energy is correct?
B < Be < N < C
Be > B > C > N
B < Be < C < N
Be < B < C < N
An element 'Y' emits one -and two - particles to give 'X'. X and Y are
isotones
isobars
isotopes
isoelectronics
Consider the following pairs of ions:
I. Sc3+ and Ti4+ II. Mn2+ and Fe2+
III. Fe2+ and Co3+ IV. Cu+ and Zn2+
Among these pairs ofions, isoelectronic pairs would include:
II, III and IV
I, III and IV
I, II and IV
I, II and III
The line spectrum of He+ ion will resemble that of :
hydrogen atom
Li+ ion
helium atom
lithium atom
A body of mass x kg is moving with a velocity of 100 ms-1. Its de-Broglie wavelength is 6.62 x 10-35 m. Hence, x is :
[h = 6.62 x 10-34Js]
0.1 Kg
0.25 Kg
0.15 Kg
0.2 Kg
The ccrrect statement with regard to and is :
both and are equally stable
both and do not exist
is more stable than
is more stable than
Ionisation potential of hydrogen atom is 13.6 eV. Hydrogen atom in ground state is excited by monochromatic light of energy 12.1 eV. The spectral lines emitted by hydrogen according to Bohr's theory will be
one
two
three
four
C.
three
Since ionisation potential of hydrogen atom is 13.6 eV.
E1 = -13.6 eV
Now, En - E1 = -(-13.6) = 12.1
+13.6 = 12.1
Therefore, n = 3
After absorbing 12.1 eV, the electron of H-atom is excited to 3rd shell.
Thus, possible transitions are 3 i.e., 3 2, 2 1 and 3 1.