The general electronic configuration of the transition elements is
(n-1)d10, (n+1)s2
(n- 1)d1-10, (n + 1)s1-2
(n- 1)d1-10, np6,ns2
(n- 1)d1-10, ns1-2
Which gives + 7 oxidation state ?
Mn(25)
Cr (24)
Cu(29)
Fe(26)
A.
Mn(25)
For d- block elements,
Oxidation state = ns electrons + (n - 1)d electrons (unpaired)
a. Mn(25) = [Ar] 3d5 4s2
Oxidation state = 5 + 2 = 7
b. Cr(24) = [Ar] 3d5 4s1
Oxidation state = 5 + 1 = 6
c. Cu(29) = [Ar] 3d10 4s1
Oxidation state = 0 + 1 = 1
d. Fe(26) = [Ar] 3d10 4s1
Oxidation state = + 2 and + 3
Among all the given options, only Mn exhibits + 7 oxidation state.
Select the coloured compound amongst the following .
(At. no. Ti= 22, Cr= 24, Cu= 29, Zn= 30)
TiCl4
CrCl3
ZnCl3
CuCl