Select the coloured compound amongst the following .(At. no. Ti=

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 Multiple Choice QuestionsMultiple Choice Questions

61.

The general electronic configuration of the transition elements is

  • (n-1)d10, (n+1)s2

  • (n- 1)d1-10, (n + 1)s1-2

  • (n- 1)d1-10, np6,ns2

  • (n- 1)d1-10, ns1-2


62.

Which of the following ions is colourless in solution?

  • V3+

  • Cr3+

  • Co2+

  • Sc3+


63.

Most common oxidation states of Ce (cerium) are

  • +3, +4

  • +2, +3

  • +2, +4

  • +3, +5


64.

Most basic hydroxide among the following is

  • Lu(OH)3

  • Eu(OH)3

  • Yb(OH)3

  • Ce(OH)3


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65.

Most common oxidation states shown by cerium are

  • +2, +4

  • +3, +4

  • +3, +5

  • +2, +3


66.

Which gives + 7 oxidation state ?

  • Mn(25)

  • Cr (24)

  • Cu(29)

  • Fe(26)


67.

Which of the following transitions involves maximum amount of energy?

  • M-(g)M(g)

  • M(g) M(g)+

  • M(g)+  M(g)2+

  • M(g)2+ M(g)3+


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68.

Select the coloured compound amongst the following .

(At. no. Ti= 22, Cr= 24, Cu= 29, Zn= 30)

  • TiCl4

  • CrCl3

  • ZnCl3

  • CuCl


B.

CrCl3

22Ti = [Ar] 3d2 4s2        Ti4+ = [Ar]
(No unpaired electron)

 34Cr = [Ar] 3d5 4s1   Cr3+= (Ar] 3d3

 

(Three unpaired electrons)

30Zn =[Ar] 3d10 4s2     Zn = [An] 3d10

(All electrons paired)

29Zn =[Ar] 3d10 4s2     Zn+ = [An] 3d10

(All electrons paired)

Since, Cr3+ ion has 3 unpaired electrons, therefore its salt, i.e., CrCl3 will be coloured.


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69.

The only radioactive element among the lanthanoids is

  • gadolinium

  • holmium

  • promethium

  • neodymium


70.

Identify a 'chemical twin' among the following.

  • Zr-Ta

  • Nb-Tc

  • Hf-Re

  • Nb-Ta


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