If the volume of spherical ball is increasing at the rate of 4 cm3/s, then the rate of change of its surface area when the volume is 288 cm3, is
The equation of displacement of a particle is x(t) = 5t2 - 7t + 3. The acceleration at the moment when its velocity becomes 5 m/sec is
3 m/sec2
7 m/sec2
10 m/sec2
8 m/sec2
The function
increases in (0, 1) but decreases in (1, 2)
decreases in (0, 2)
increases m (1, 2) but decreases in (0, 1)
increases in (0, 2)
The points of the curve y = x3 + x - 2 at which its tangent are parallel to the straight line y = 4x - 1 are
(2, 7), (- 2, - 11)
(0, 2), (21/3, 21/3)
(- 21/3, - 21/3), (0, - 4)
(1, 0), (- 1, - 4)
The equation of the normal to the curve y = - + 2 at the point of its intersection with the bisector of the first quadrant is
4x - y + 16 = 0
4x - y = 16
2x - y - 1 = 0
2x - y + 1 = 0