If the normal to the curve y = f(x) at the point (3, 4) make an angle 3/4 with the positive x-axis, then f'(3) is
1
- 1
-
The equation of normal of x2 + y2 - 2x + 4y - 5 = 0 at (2, 1) is
y = 3x - 5
2y = 3x - 4
y = 3x + 4
y = x + 1
A.
y = 3x - 5
Given equation is,
x2 + y2 - 2x + 4y - 5 = 0
On differentiating, we get