The equation of normal of x2 + y2 - 2x + 4y - 5 = 0 at (2, 1

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40.

The equation of normal of x+ y2 - 2x + 4y - 5 = 0 at (2, 1) is

  • y = 3x - 5

  • 2y = 3x - 4

  • y = 3x + 4

  • y = x + 1


A.

y = 3x - 5

Given equation is,

x+ y2 - 2x + 4y - 5 = 0

On differentiating, we get

2x +2ydydx - 2 +4dydx = 0 y + 2dydx = 1 - x dydx2, 1 = 1 - 21 + 2 = - 13 - dxdy2, 1 = 3Now, equation of nrmal is(y - 1) = 3(x - 2)  y - 1 = 3x - 6     y = 3x - 5


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