The distance covered by a particle in t seconds is given by x = 3 + 8t - 4t2. After 1 s its velocity will be
0 unit/s
3 unit/s
4 unit/s
7 unit/s
If the tangent to the parabola y = x(2 - x) at the point (1, 1) intersects the parabola at P. Find the coordinate of P.
A particle moves along a straight line according to the laws = 16- 2t + 3t, where s metres is the distance of the particle from a fixed point at the end of t seconds. The acceleration of the particle at the end of 2s is
36m/s2
34m/s2
36m
None of these
For the curve y = xe, the point
x = - 1 is a point of minimum
x = 0 is a point of minimum
x = - 1 is a point of maximum
x = 0 is a point of maximum
If the slope of the curve at the point (1, 1) is 2, then
a = 1, b = - 2
a = - 1, b = 2
a = 1, b = 2
None of these
If the tangent at (1, 1) on y = x(2 - x)2 meets the curve again at P, then P is
(4, 4)
(- 1, 2)
(9/4, 3/8)
None of these
C.
(9/4, 3/8)
We have,
y2 = x(2 - x)2 ...(i)
y2 = x3 - 4x2 + 4x
On differentiating both sides w.r.t. x we get
The equation of the tangent at (1, 1) is
y - 1 = - 1/2 (x - 1)
On solving Eq. (i) and (ii), we get x = 9/4 and y = 3/8
Hence, the coordinates of Pare (9/4, 3/8).
If there is an error of K % is measuring the edge of a cube, then the per cent error in estimating its volume is
k
3k
None of these