Sum of the last 30 coefficients in the expansion of (1 + x)59 , when expanded in ascending power of x is
259
258
230
229
If C0, C1, C2, ..., Cn denote the coefficients in the expansion of (1 + x)n, then the value of C1 + 2C2 + 3C3 + ... + nCn is
n . 2n - 1
(n + 1)2n - 1
(n + 1)2n
(n + 2)2n - 1
A.
n . 2n - 1
Since,
(1 + x)n = C0 + x . C1 + x2 . C2 + ... + xn . Cn
On differentiating both sides w.r.t. x, we get
n(1 + x)n - 1 = C1 + 2xC2 + ... + nxn - 1Cn
Put x = 1, we get
n(2)n - 1 = C1 + 2. C2 + 3 . C3 + ... n . Cn
If the coefficients of x2 and x3 in the expansion of (3 + ax)9 be same, then the value of 'a' is
3/7
7/3
7/9
9/7
Using binomial theorem, the value of (0.999)3 correct to 3 decimal places is
0.999
0.998
0.997
0.995
Show that, for a positive integer n, the coefficient of xk, () in the expansion of 1 + (1 + x) + (1 + x) + ... + (1 + x)n is