If a, b, c are real, then both the roots of the equation (x - b)(x - c) + (x - c)(x - a) + (x - a)(x - b) = 0
positive
negative
real
imaginary
C.
real
Given equation can be rewritten as,
3x2 - 2x(a + b + c) + ab + bc + ca = 0
Now, Discriminant,
D = 4(a + b + c)2 - 4 . 3(ab + bc + ca)
= 4(a2 + b2 + c2 - ab - bc - ca)
= 2[(a - b)2 + (b - c)2 + (c - a)2]
0
Hence, roots are real.
The quadratic equation whose roots are three times the roots of 3ax2 + 3bx + c = 0 is
ax2 + 3bx + 3c = 0
ax2 + 3bx + c
9ax2 + 9bx + c
ax2 + bx + 3c
Find the values of 'a' for which the expression x2 - (3a - 1)x + 2a2 + 2a - 11 is always positive
The value of (1 - w + w2)5 + (1 + w - w2)5, where w and w2 are the complex cube roots of unity, is
0
32w
- 32
32