If are the roots of x2 - ax + b = 0 and if = Vn, then
Vn + 1 = aVn + bVn - 1
Vn + 1 = aVn + aVn - 1
Vn + 1 = aVn - bVn - 1
Vn + 1 = aVn - 1 + bVn
If the complex numbers z1, z2 and z3 are in AP, then they lie on a
circle
parabola
line
ellipse
The number of real solutions of the equation
is
0
1
2
None of these
A.
0
Let f (x) = - 3 + x - x2
Then, f(x) < 0 for all x because coefficient of x2 < 0 and disc < 0. Thus, LHS of the given equation is always positive whereas the RHS is always less than zero. Hence, the given equation has no. solution.
If one root is square of the other root of the equation x2 + px + q = 0 , then the relations between p and q is
p3 - (3p - 1)q + q2 = 0
p3 - q(3p + 1) + q2 = 0
p3 + (3p - 1)q + q2 = 0
p3 + (3p + 1)q + q2 = 0