The transverse axis of a hyperbola is along the x - axis and its length is 2a. The vertex of the hyperbola bisects the line segment joining the centre and the focus. The equation of the hyperbola is
6x2 - y2 = 3a2
x2 - 3y2 = 3a2
x2 - 6y2 = 3a2
3x2 - y2 = 3a2
A point moves in such a way that the difference of its distance from two points (8, 0) and (- 8, 0) always remains 4. Then, the locus of the point is
a circle
a parabola
an ellipse
a hyperbola
Let C1 and C2 denote the centres of the circles x2 + y2 = 4 and (x - 2)2 + y2 = 1 respectively and let P and Q be their points of intersection. Then, the areas of C2PQ and CPQ are in the ratio
3 : 1
5 : 1
7 : 1
9 : 1
The incentre of an equilateral triangle is (1, 1) and the equation of one side is 3x + 4y + 3 = 0. Then, the equation of the circumcircle of the triangle is
x2 + y2 - 2x - 2y - 2 = 0
x2 + y2 - 2x - 2y - 14 = 0
x2 + y2 - 2x - 2y + 2 = 0
x2 + y2 - 2x - 2y + 14 = 0
The length of the latus rectum of the ellipse 16x2 + 25y2 = 400 is
5/16 unit
32/5 unit
16/5 unit
5/32 unit
The coordinates of a moving point P are (2t2 + 4, 4t + 6). Then, its locus will be
circle
straight line
parabola
ellipse
The equation 8x2 + 12y2 - 4x + 4y - 1 = 0 represents
an ellipse
a hyperbola
a parabola
a circle
A.
an ellipse
Given equation is
8x2 + 12y2 - 4x + 4y - 1 = 0
It is comapring by
ax2 + by2 + 2hxy + 2gx + 2fy + c = 0
We get,
a = 8, b = 12, h = 0, g = - 2, f = 2, c = - 1
Hence it represents an ellipse
If the straight line y = mx lies outside the circle x2 + y2 - 20y + 90 = 0, then the value of m will satisfy
m < 3
m > 3