The area (in square unit) of the circle which touches the lines 4

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

191.

The equation λx2 + 4xy + y2 + λx + 3y + 2 = 0 represents parabola, if λ is

  • 0

  • 1

  • 2

  • 4


192.

If two circles 2x2 + 2y2 - 3x + 6y + k = 0 and x2 + y2 - 4x + 10y + 16 = 0 cut orthagobally then, value of k is

  • 41

  • 14

  • 4

  • 1


193.

The locus of z satisfying the inequality z +2i2z +i < 1, where z = x + iy, is

  • x2 + y2 < 1

  • x2 - y2 < 1

  • x2 + y2 > 1

  • 2x2 + 3y2 < 1


Advertisement

194.

The area (in square unit) of the circle which touches the lines 4x + 3y = 15 and 4x + 3y = 5 is

  • 4π

  • 3π

  • 2π

  • π


D.

π

Since, given lines are parallel.

 d = 15 - 543 + 32 = 105 d = 2 = diameter of the circle Radius of circle = 1    Area of circle = πr2 = π sq unit


Advertisement
Advertisement
195.

The equations of the circle which pass through the origin and makes intercepts of lengths 4 and 8 on the x and y -axes respectively are

  • x2 + y2 ± 4x ± 8y = 0

  • x2 + y2 ± 2x ± 4y = 0

  • x2 + y2 ± 8x ± 16y = 0

  • x2 + y2 ± x ± y = 0


196.

The point (3 -4) lies on both the circles x2 + y2 - 2x + 8y + 13 = 0 and x2 + y2 - 4x + 6y + 11 = 0. Then, the angle between the circles is

  • 60°

  • tan-112

  • tan-135

  • 135°


197.

The equation of the circle which passes through the origin and cuts orthogonally each of the circles x+ y2 - 6x + 8 = 0 and x2 + y2 - 2x - 2y = 7 is

  • 3x2 + 3y2 - 8x - 13y = 0

  • 3x2 + 3y2 - 8x + 29y = 0

  • 3x2 + 3y2 + 8x + 29y = 0

  • 3x2 + 3y2 - 8x - 29y = 0


198.

The number of normals drawn to the parabola y2 = 4x from the point (1, 0) is

  • 0

  • 1

  • 2

  • 3


Advertisement
199.

If the circle x2 + y2 = a intersects the hyperbola xy = cin four points (xi, yi), for i = 1, 2, 3 and 4, then y1 + y2 + y3 + y4 equals

  • 0

  • c

  • a

  • c4


200.

The mid point of the chord 4x - 3y = 5 of the hyperbola 2x- 3y2 = 12 is

  • 0, - 53

  • (2, 1)

  • 54, 0

  • 114, 2


Advertisement