Let M be the foot of the perpendicular from a point P on the para

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441.

Let M be the foot of the perpendicular from a point P on the parabola y = 8(x - 3) onto its directrix and let S be the focus ofthe parabola. If  SPM is an equilateral triangle, then P is equal to

  • (43, 8)

  • (8, 43)

  • (9, 43)

  • (43, 9)


C.

(9, 43)

Given, that the SPM is equilateralAlso, given parabola is y2 = 8x - 3 focus of this parabola is S(5, 0) and vertex A(3, 0)

Let coordinate of P (h + at2, k + 2at) = P(3 + 2t2, 4t)

Then, coordinate of M(- 5, 4t)

We know that the side of this  equilateral trianle is 4a = 4 x 2 = 8

Now, PS = 8

3 + 2t2 - 52 + 4t2 = 8   2t2 - 22 + 4t2 = 8                       2t2 + 2 = 8                              2t2 = 6                                 t = 3

 P3 + 2 × 3, 4 × 3 = P9, 43


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442.

Consider the circle x2 + y - 4x - 2y + c = 0 whose centre is A(2, 1). If the point P(10, 7) is such that the line segment PA meets the circle in Q with PQ = 5, then c is equal to

  • - 15

  • 20

  • 30

  • - 20


443.

The foci of the ellipse x216 + y2b2 = 1 and the hyperbola x2144 - y281 = 125 coincide. Then, the value of b2 is 

  • 5

  • 7

  • 9

  • 1


444.

The tangents to the parabola y = 4ax from an external point P make angles θ1 and θ2, with the axis of the parabola. Such that tanθ1 + tanθ2 = b where b is constant. Then P lies on

  • y = x + b

  • y + x = b

  • y = xb

  • y = bx


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445.

The area (in sq. units) of the largest rectangle ABCD whose vertices A and B lie on the x-axis and vertices C and D lie on the parabola, y = x2 – 1 below the x-axis, is

  • 133

  • 43

  • 433

  • 233


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