The value of f(0) so that may be continuous at x = 0 is
0
4
- 1 +
D.
- 1 +
Let [ ] denotes the greatest integer function and f(x) = [tan2(x)] Then,
does not exist
f(x) is continuous at x = 0
f(x) is not differentiable at x = 0
f(x) = 1
If f(x) = (x - 2)(x - 4)(x - 6) ... (x - 2n), then f'(2) is
(- 1)n2n - 1 (n - 1)!
(- 2)n - 1 (n - 1)!
(- 2)n n!
(- 1)n - 12n (n - 1)!