The value of c in (0, 2) satisfying the mean value theorem for the function f(x) = x(x - 1)2, x [0, 2] is equal to
The value of x in the interval [ 4, 9] at which the function f(x) = satisfies the mean value theorem is
If the function f(x) = is continuous everywhere, then the values of c and k are respectively.
- 3, - 5
- 3, 5
- 3, - 4
- 3, 4
If x2 + 2xy + 2y2 = 1, then at the point where y = 1 is equal to
1
2
- 1
0
D.
0