If f(x) = , then f(x) is differentiable on
[- 1, 1]
R - {- 1, 1}
R - (- 1, 1)
None of these
B.
R - {- 1, 1}
Hence, f (x) is differentiable on R - {- 1, 1}.
The function f (x) = is
continuous everywhere but not differentiable at x = 0
continuous and differentiable everywhere
not continuous at x = 0
None of the above
If y2 = ax2 + bx + c, where a, b, c are constants, then is equal to
a constant
a function of x
a function of y
a function of x and y both