Let f(x) = x, x2 for –10 

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451.

Let f(x) = x, x2 for 10 < x < 10, where [t] denotes the greatest integer function. Then the number of points of discontinuity of f is equal to ____


Ans : 8

 - 5 < x2 < 5 x2 = - 5, - 4, - 3, - 2, - 1, 0, 1, 2, 3, 4Hence function is discontinues at = - 4, - 3, - 2, - 1, 1, 2, 3, 4Number of values is 8


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452.

Let f : R   R be defined asfx = x5sin1x + 5x2, x < 00, x = 0x5cos1x + λx2, x > 0The value of λ for which f''0 exists, is


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