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Continuity and Differentiability

Short Answer Type

451.

Ans : 8

452.

$Let f : R \to R be defined as f (x) = \{x^{5} \sin (\frac{1}{x}) + 5 x^{2}, x < 0 0, x = 0 x^{5} \cos (\frac{1}{x}) + {λx}^{2}, x > 0\} The value of λ for which f'' (0) exists, is$