The differential equation of the family of curves y = e2x(acos(x) + bsin(x)), where a and b are arbitrary constants, is given by
y2 - 4y1 + 5y = 0
2y2 - y1 + 5y = 0
y2 + 4y1 - 5y = 0
y2 - 2y1 + 5y = 0
The differential equation has the solution
x = y(log(x) + C)
y = x(log(y) + C)
x = (y + C)log(x)
y = (x + C)log(y)
The degree of the differential equation satisfying
1
2
3
None
A.
1
We have,
On putting x = sin(A), y = sin(B), we get
cos(A) + cos(B) = a(sin(A) - sin(B))
Clearly, it is differential equation of first order and first degree.