The solution of the differential equation is
y = ex + C
y = x + ex + C
y = xex + C
y = x(ex + 1) + C
If x2 + y2 = 1, then
yy'' + (y')2 + 1 = 0
yy'' +2 (y')2 + 1 = 0
yy'' - 2(y')2 + 1 = 0
yy'' + (y')2 - 1 = 0
A.
yy'' + (y')2 + 1 = 0
It is given that, x2 + y2 = 1
On differentiating both sides w.r.t. x, we get
2x + 2y y' = 0
x + yy' = 0
Again, on differentiating, we get
1 + y' . y' + y . y'' = 0
yy'' + (y')2 + 1 = 0
The solution of the differential equation y'(y2 - x) = y is
y3 - 3xy = C
y3 + 3xy = C
x3 - 3xy = C
y3 - xy = C
The order and degree of the differential equation are respectively
2 and 2
2 and 1
3 and 2
3 and 3
The slope of a curve at any point (x, y) other than the origin, is y + . Then, the equation of the curve is
y = C xex
y = x(ex + C)
xy = Cex
y + xex = C
The general solution of the differential equation is
x + y + 3 = Cey
x + y + 4 = Cey
x + y + 3 = Ce- y
x + y + 4 = Ce- y
The differential equation representing the family of curves y2 = a(ax + b), where a and b are arbitrary constants, is of
order 1, degree 1
order 1, degree 3
order 2, degree 3
order 2, degree 1