The solution of differential equation (x + y )(dx - dy) = dx + dy is :
x - y = kex - y
x + y = kex + y
x + y = k(x - y)
x + y = kex - y
The integrating factor of the differential equation = 1 is :
D.
Solution of the differential equation tan(y) . sec2(x)dx + tan(x) · sec2(y)dy = 0 is
tan(x) + tan(y) = k
tan(x) - tan(y) = k
The solution of 2(y + 3) - xy = 0 with y = - 2,when x = 1 is
(y + 3) = x2
x2(y + 3) = 1
x4(y + 3) = 1
x2(y + 3)3 = ey + 2
Let f : R R be a differentiable function and f(1) = 4. Then the value of , if f'(1) = 2 is :
16
8
4
2