The solution of the differential equation x + 2y3dydx = Y is
y3 + Cx = y
xy42 + xy = Cy
y3 + Cy = x
x + 2y3 = y + C
The solution ofthe differential equation
dydx = ylogy - logx + 1x is
x = yecy
y = xecy
x = yecx
None of these
The solution of the differential equationdydx + siny + x2 + siny - x2 = 0 is
logtany2 = C - 2sinx
logtany4 = C - 2sinx2
logtany2 + π4 = C - 2sinx
logtany2 + π4 = C - 2sinx2
The solution of differential equation x2 + y2 - 2xydydx = 0 is
x2 + y2 = xC
x2 - y2 = xC
x2 + y2 = C
x2 - y2 = C
The solution of differential equation dydx = x2logx + 1siny + ycosy is
ysiny = x2logx + C
y = x2 + logx + C
ysiny = x2 + C
Solution of 2ysinxdydx = 2sinxcosx - y2cosx, x = π2, y = 1 is given by
y2 = sin(x)
y = sin2(x)
y2 = cos(x) + 1
Solution of x2dydx - xy = 1 + cosyx is
tany2x = C - 12x2
tanyx = C + 1x
cosyx = 1 + Cx
x2 = C + x2tanyx
The solution of dydx = cosx2 - ycscx where y = 2, when x = π2 is
y = sinx + cscx
y = tanx2 + cotx2
y = 12secx2 + 2cosx2
None of the above
A.
Given, dydx = cosx2 - ycscx dydx = 2cosx - ycotx⇒ dydx + ycotx = 2cosx IF = e∫cotxdx = sinx ysinx = ∫2cosx . sinxdx + C ysinx = sin2x + Cat y = 2 and x = π2⇒ C = 1∴ ysinx = sin2x + 1 ∵ from Eq. (i)⇒ y = sinx + cscx
The solution of the equation sin-1dydx = x + y is
tanx + y + secx + y = x + C
tanx + y - secx + y = x + C
tanx + y - secx + y + x + C = 0
The solution of differential equation
4xydydx = 31 + x21 + y21 + x2 is
log1 + y = logx + 2tanx + C
log1 + y2 = 3log1x + 6tan-1x + C
log1 + y2 = 3logx + 6tan-1x + C