Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Integrals

Multiple Choice Questions

161.

$\int e^{3 \log (x)} {(x^{4} + 1)}^{- 1} dx$ is equal to

e³^log(x) + c
$\frac{1}{4} \log (x^{4} + 1)$
log(x⁴ + 1) + c
$\frac{1}{2} \log (x^{4} + 1) + c$

162.

If $\int_{0}^{π} xf (\sin (x)) dx = A \int_{0}^{\frac{π}{2}} f (\sin (x)) dx$ , then A is

0
$π$
$\frac{π}{4}$
2 $π$

163.

$\int_{- 2}^{2} |[x]| dx$ is equal to

164.

If $\int \frac{\sin (x)}{\sin (x - α)} dx = Ax + Blog (\sin (x - α)) + C$ , then value of A - B at $α = \frac{π}{2}$ is

165.

If $\int_{a}^{b} x^{3} dx = 0 and \int_{a}^{b} x^{2} dx = \frac{2}{3}$ , then the values of a and b are respectively

1, - 1
- 1, 1
1, 1
- 1, - 1

166.

$\int (\sqrt[3]{x}) (\sqrt[5]{1 + \sqrt[3]{x^{4}}}) dx$ is equal to

${(1 + x^{\frac{3}{4}})}^{\frac{6}{5}} + c$
${(1 + x^{\frac{4}{3}})}^{\frac{6}{5}} + c$
$\frac{5}{8} {(1 + x^{\frac{4}{3}})}^{\frac{6}{5}} + c$
$\frac{1}{6} {(1 + x^{\frac{4}{3}})}^{6} + c$

167.

If u = - $f'' (θ) \sin (θ) + f' (θ) \cos (θ)$ and v = $f'' (θ) \cos (θ) + f' (θ) \sin (θ)$ , then $\int {[{(\frac{du}{dθ})}^{2} + {(\frac{dv}{dθ})}^{2}]}^{\frac{1}{2}} dθ$ is equal to

$f (θ) - f'' (θ) + c$
$f (θ) + f'' (θ) + c$
$f' (θ) + f'' (θ) + c$
$f' (θ) - f'' (θ) + c$

168.

$\int \frac{e^{6 \log_{e} (x)} - e^{5 \log_{e} (x)}}{e^{4 \log_{e} (x)} - e^{3 \log_{e} (x)}} dx$ is equal to

$\frac{x^{3}}{3} + c$
$\frac{x^{2}}{2} + c$
$\frac{x^{2}}{3} + c$
$\frac{- x^{3}}{3} + c$

169.

$\int e^{x} {(\frac{1 - x}{1 + x^{2}})}^{2} dx$ is equal to

$e^{x} (\frac{1 - x}{1 + x^{2}}) + c$
$e^{x} (\frac{1}{1 + x^{2}}) + c$
$e^{x} (\frac{1 + x}{1 + x^{2}})$
$e^{x} (\frac{1 - x}{{(1 + x^{2})}^{2}}) + c$

170.
$\int \frac{x^{4} - 1}{x^{2} {(x^{4} + x^{2} + 1)}^{\frac{1}{2}}} dx$ is equal to

$\sqrt{\frac{x^{4} + x^{2} + 1}{x}} + c$

$\frac{x^{2}}{\sqrt{x^{4} + x^{2} + 1}} + c$

$x {(x^{4} + x^{2} + 1)}^{\frac{3}{2}} + c$

$\frac{\sqrt{x^{4} + x^{2} + 1}}{x} + c$

$\frac{\sqrt{x^{4} + x^{2} + 1}}{x} + c$

$\int \frac{x^{4} - 1}{x^{2} {(x^{4} + x^{2} + 1)}^{\frac{1}{2}}} dx = \int \frac{2 x^{4} + x^{2} - (x^{4} + x^{2} + 1)}{x^{2} \sqrt{x^{4} + x^{2} + 1}} dx = \int \frac{\frac{x (4 x^{3} + 2 x)}{2 \sqrt{x^{4} + x^{2} + 1}} - \sqrt{x^{4} + x^{2} + 1}}{x^{2}} dx = \int \frac{d}{dx} (\frac{\sqrt{x^{4} + x^{2} + 1}}{x}) = \frac{\sqrt{x^{4} + x^{2} + 1}}{x} + c$

Previous Year Papers

Test Series

Test Yourself

Multiple Choice Questions

170. ∫x4 - 1x2x4 + x2 + 112dx is equal to x4 + x2 + 1x + c x2x4 + x2 + 1 + c xx4 + x2 + 132 + c x4 + x2 + 1x + c

170.
$\int \frac{x^{4} - 1}{x^{2} {(x^{4} + x^{2} + 1)}^{\frac{1}{2}}} dx$ is equal to

$\sqrt{\frac{x^{4} + x^{2} + 1}{x}} + c$

$\frac{x^{2}}{\sqrt{x^{4} + x^{2} + 1}} + c$

$x {(x^{4} + x^{2} + 1)}^{\frac{3}{2}} + c$

$\frac{\sqrt{x^{4} + x^{2} + 1}}{x} + c$