∫1xlogxloglogxdx is equal to from Mathematics Integrals

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 Multiple Choice QuestionsMultiple Choice Questions

201.

exxxlogx + 1dx is equal to

  • exx + C

  • xexlogx + C

  • exlogx + C

  • x(exlogx) + C


202.

1 + logx1 + x logx2dx is equal to

  • 11 + xlogx + C

  • 11 + logx + C

  • - 11 + xlogx + C

  • log11 + logx + C


203.

1 - tan2xdx is equal to

  • tanx + C

  • secx + C

  • 2x - secx + C

  • 2x - tanx + C


204.

The value of 06x - 3dx is equal to

  • 6

  • 0

  • 12

  • 9


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205.

If f(x) = 2xsinxcost3dt, then f'(x) is equal to

  • cossin3xcosx - 2cos8x3

  • sinsin3xsinx - 2sin8x3

  • coscos3xcosx - 2cosx3

  • cossin3x - cos8x3


206.

010x1010 - x10 + x10dx is equal to

  • 10

  • 5

  • 2

  • 12


207.

The value of 01xexdx is equal to

  • e - 22

  • 2(e - 2)

  • 2e - 1

  • 2(e - 1)


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208.

1xlogxloglogxdx is equal to

  • loglogx + C

  • loglogxlogx + C

  • loglogloglogx + C

  • logloglogx + C


D.

logloglogx + C

Let I = 1xlogxloglogxdxPut, t = loglogx dtdx = 1xlogx xlogxdt = dx

Then, I = dtt = logt +C            = logloglogx + C


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209.

3x1 - 9xdx is equal to

  • log3sin-13x + C

  • 13sin-13x + C

  • 13sin-13x +C

  • 19sin-13x +C


210.

The value of the integral cosxsinx + cosxdx is equal to

  • x + logsinx + cosx + C

  • 12x + logsinx + cosx +C

  • logsinx + cosx + C

  • x2 + logsinx + cosx + C


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