∫0π2logcosxsinxdx is equal to from Mathematics Integ

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 Multiple Choice QuestionsMultiple Choice Questions

241.

0π22x3sinx2dx is equal to

  • 121 + π4

  • 121 - π4

  • 12π2 - 1

  • 121 - π2


242.

secxmtan3x + tanxdx is equal to

  • secm + 2x + C

  • tanm +2x + C

  • secm + 2xm + 2 +C

  • tanm + 2xm + 2 +C


243.

17sinx7 + 10dx is equal to

  • 17cosx7 + 10 + C

  • - 17cosx7 + 10dx

  • - cosx7 + 10 + C

  • - 7cosx7 + 10 + C


244.

x - ax - xx +adx is equal to

  • logx + ax + C

  • alogx + ax + C

  • alogxx +a + C

  • logx + ax + C


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245.

x4ex5cosex5dx is equal to

  • 13sinex5 + C

  • 14sinex5 + C

  • 15sinex5 + C

  • sinex5 + C


246.

1sinxcosxdx is equal to

  • logtanx + C

  • logsin2x + C

  • logsecx + C

  • logcosx + C


247.

2x + sin2x1 + cos2xdx is equal to

  • x + logtanx + C

  • xlogtanx + C

  • xtanx + C

  • x + tanx + C


248.

18sin2x + 1dx is equal to

  • sin-1tanx + C

  • 13sin-1tanx + C

  • 13tan-13tanx + C

  • tan-13tanx + C


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249.

0π2logcosxsinxdx is equal to

  • π2

  • π4

  • π

  • 0


D.

0

Let I = 0π2logcosxsinxdx = 0π2logcotxdx        ...iThen, I = 0π2logcotπ2 - xdx                    abfxdx = abfa + b - xdx            = 0π2logtanxdx                ...iiOn adding Eqs. (i) and (ii), we get   2I = 0π2logcotx + logtanxdx   2I = 0π20dx = 0 I = 0


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250.

The value of - 124x2xdx is equal to

  • 17

  • 16

  • 15

  • 14


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