The value of ∫0π2cos3x + 12cosx - 

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

351.

cos3x . elogsinxdx is equal to

  • - sin4x4 + c

  • - cos4x4 + c

  • esinx4 +c

  • None of the above


Advertisement

352.

The value of 0π2cos3x + 12cosx - 1dx is

  • 2

  • 1

  • 12

  • 0


B.

1

Let I = 0π2cos3x + 12cosx - 1dx= 0π2cos3x - cos3π32cosx - cosπ3dx= 0π24cos3x - 3cosx - 4cos3π3 - 3cosπ32cosx - cosπ3dx= 20π2cos3x - cos3π3cosx - cosπ3dx - 320π2cosx - cosπ3cosx - cosπ3dx= 20π2cos2x + cos2π3 + cosxcosπ3 - 320π21dx= 0π21 + cos2x + 12 + cosxdx - 3π4= 3π4 + 1 - 3π4 = 1


Advertisement
353.

The value of 01tan-12x - 11 + x - x2dx is

  • 1

  • 0

  • - 1

  • None of the above


354.

By the application of Simpson's one - third rule for numerical integration, with two subintervals, the value of 01dx1 +x is

  • 1736

  • 1725

  • 2536

  • 1724


Advertisement
355.

xe - 1 + ex - 1xe + exdx is equal to

  • logxe + ex +c

  • elogxe + ex +c

  • 1elogxe + ex +c

  • None of the above


356.

The value of π4π2exlogsinx + cotxdx is

  • eπ4log2

  • - eπ4log2

  • 12eπ4log2

  • - 12eπ4log2


357.

Considering four sub-intervals, the value of 0111 +xdx by Trapezoidal rule, is

  • 0.6870

  • 0.6677

  • 0.6977

  • 0.5970


358.

By Simpson's rule, the value of 12dxx dividing the interval (1, 2) into four equal parts, is

  • 0.6932

  • 0.6753

  • 0.6692

  • 7.1324


Advertisement
359.

The value of xsinxsec3xdx is

  • 12sec2x - tanx + c

  • 12xsec2x - tanx + c

  • 12xsec2x + tanx + c

  • 12sec2x + tanx + c


360.

The value of 0xxsin3xdx is

  • 4π3

  • 2π3

  • 0

  • None of these


Advertisement