The point of inflection of the function y = ∫0xt2 -

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 Multiple Choice QuestionsMultiple Choice Questions

401.

03xdx = ..., where [x] is greatest integer function

  • 3

  • 0

  • 2

  • 1


402.

sec8xcscxdx =

  • sec8x8 + c

  • sec7x7 + c

  • sec6x6 + c

  • sec9x9 + c


403.

The tangent to the graph of a continuous function y = f(x) at the point with abscissa x = a forms with the X-axis an angle of π3 and at the point with abscissa x = b an angle of π4, then what the value of integral abf'x + f''xdx

(where f'(x) the derivative off w.r.t. xwhich is assumed to be continuous and similarly f"(x) the double derivative of f w.r.t. x)

  • eb3ea

  • eb - 3ea

  • eb - 3ea

  • - eb - 3ea


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404.

The point of inflection of the function y = 0xt2 - 3t + 2dt is

  • 32, 34

  • - 32, - 34

  • - 12, - 32

  • 12, 32


A.

32, 34

Given y = 0xt2 - 3t + 2dt    ...iOn dlfferentiating w. r. t. 'x', we get dydx = x2 - 3x + 2     ...iiAgain, on differentiating w.r.t. 'x', we getd2ydx2 = 2x - 3             ...iiiWe know that, at point of inflectond2ydx2 = 0 From Eq (iii), we get2x - 3 = 0  x = 32Now, we have to check behaviour of d2ydx2 at point x = 32Clearly, as x = 32 sign at d2ydx2 changes 32, 34 is a point of inflection.


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405.

The value of integral dxxx2 - a2

  • c - 1asin-1ax

  • c - 1acos-1ax

  • sin-1ax + c

  • c + 1asin-1ax


406.

The value of 012sin-1x1 - x232dx is

  • π2 - log2

  • π4 - 12log2

     

  • π4 + 12log2

  • π - 12log2


407.

Integral of 12 + cosx

  • 13tan-112tanx +C

  • 23tan-113tanx2 +C

  • - sinxlog2 + cosx + C

  • sinxlog2 + cosx + C


408.

dxx4 + x6 is equal to

  • - 1 + x2x + C

  • 1 + x2x + C

  • - 1 - x2x + C

  • - x2 - 1x + C


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409.

If sin-1xcos-1xdx = f-1xπ2x - xf-1x - 21 - x2

π21 - x2 + 2x +C, then

  • f(x) = sin(x)

  • f(x) = cos(x)

  • f(x) = tan(x)

  • None of these


410.

If 0πxfsin2x + sec2xdx = k0π2fsin2x + sec2xdx, then the value of k is

  • π2

  • π

  • - π2

  • None of these


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