Integral of 12 + cosx from Mathematics Integrals

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 Multiple Choice QuestionsMultiple Choice Questions

401.

03xdx = ..., where [x] is greatest integer function

  • 3

  • 0

  • 2

  • 1


402.

sec8xcscxdx =

  • sec8x8 + c

  • sec7x7 + c

  • sec6x6 + c

  • sec9x9 + c


403.

The tangent to the graph of a continuous function y = f(x) at the point with abscissa x = a forms with the X-axis an angle of π3 and at the point with abscissa x = b an angle of π4, then what the value of integral abf'x + f''xdx

(where f'(x) the derivative off w.r.t. xwhich is assumed to be continuous and similarly f"(x) the double derivative of f w.r.t. x)

  • eb3ea

  • eb - 3ea

  • eb - 3ea

  • - eb - 3ea


404.

The point of inflection of the function y = 0xt2 - 3t + 2dt is

  • 32, 34

  • - 32, - 34

  • - 12, - 32

  • 12, 32


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405.

The value of integral dxxx2 - a2

  • c - 1asin-1ax

  • c - 1acos-1ax

  • sin-1ax + c

  • c + 1asin-1ax


406.

The value of 012sin-1x1 - x232dx is

  • π2 - log2

  • π4 - 12log2

     

  • π4 + 12log2

  • π - 12log2


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407.

Integral of 12 + cosx

  • 13tan-112tanx +C

  • 23tan-113tanx2 +C

  • - sinxlog2 + cosx + C

  • sinxlog2 + cosx + C


B.

23tan-113tanx2 +C

Let I = 12 + cosxdxPut cosx = 1 - tan2x21 + tan2x2 I = 12 + 1 - tan2x21 + tan2x2 I = sec2x22 + 2tan2x2 + 1 - tan2x2dx I = sec2x23 + tan2x2dxAgain, put tanx2 = t  12sec2x2dx = dtNow, I = 2dt3 +t2     from Eq. (i)           = 2dt32 + t2           = 23tan-1tanx23 + C           = 23tan-113tanx2 +C


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408.

dxx4 + x6 is equal to

  • - 1 + x2x + C

  • 1 + x2x + C

  • - 1 - x2x + C

  • - x2 - 1x + C


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409.

If sin-1xcos-1xdx = f-1xπ2x - xf-1x - 21 - x2

π21 - x2 + 2x +C, then

  • f(x) = sin(x)

  • f(x) = cos(x)

  • f(x) = tan(x)

  • None of these


410.

If 0πxfsin2x + sec2xdx = k0π2fsin2x + sec2xdx, then the value of k is

  • π2

  • π

  • - π2

  • None of these


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