∫0πxdx1 + sinx is equal to :
- π
π2
π
None of these
∫dxxx5 + 1 is equal to :
15logx5x5 + 1 + c
15logx5 + 1x5 + c
∫x + sinx1 + cosxdx is equal to
xtanx2 + c
xsec2x2 + c
logcosx2 + c
∫0π8cos34θdθ is equal to
53
54
13
16
∫0π2cosx - sinx1 + cosx sinx dx is equal to
0
π4
π6
∫dxxx7 + 1 is equal to
logx7x7 + 1 + c
17logx7x7 + 1 + c
logx7 + 1x7 + c
17logx7 + 1x7 + c
B.
Given that, ∫dxxx7 + 1On putting x7 = t⇒7x6dx = dt⇒ dx = 17x6dt∴ I = ∫17x7dtt + 1 = 17∫1tdtt + 1 ∵ x7 = t = 17∫1t - 1t + 1 = 17logtt + 1 + c = 17logx7x7 + 1 + c
∫- 111 - xdx is equal to
- 2
2
4
∫xexdx is equal to
2x - ex - 4xex + c
2x - 4x + 4ex + c
2x + 4x + 4ex + c
1 - 4x ex + c
∫dxx2 + 2x + 2 is equal to
sin-1x + 1 + c
sinh-1x + 1 + c
tanh-1x + 1 + c
tan-1x + 1 + c
∫02πsinx + sinxdx is equal to
1
8