Intersection point of f1(x) = ∫2x2t - 5dt 

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 Multiple Choice QuestionsMultiple Choice Questions

551.

The value of f(x) is given only at x = 0, 13, 23 wich of the following can be used to evaluate 01fxdx approximately

  • Trapezoidal rule

  • Simpson's rule

  • Trapezoidal as well as Simpson's rule

  • None of the above


552.

If f(x) = ex1 + ex, I1 = f- afaxgx1 - xdx and I2 = f- afagx1 - xdx, the value of I2I1 is

  • 2

  • - 3

  • - 1

  • 1


553.

0afxdx is equal to

  • 0afa - xdx

  • 0afx - adx

  • 0af2a - xdx

  • 0afx + 2adx


554.

sin4xdx is equal to

  • 183x + sin4x4 - 4sin2x2 + c

  • 183x + sin4x4 + 4sin2x2 + c

  • 143x + sin4x4 - 4cos2x2 + c

  • 183x + sin4x4 + 4cos4x2 + c


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555.

logxdx is equal to

  • x + xlogx + c

  • xlogx - x +c

  • x2logx +c

  • 1xlogx + xc


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556.

Intersection point of f1(x) = 2x2t - 5dt and f2x = 0x2tdt is

  • 65, 3625

  • 23, 49

  • 13, 19

  • 15, 125


A.

65, 3625

Let  y1 = f1x = 2x2t - 5dt            = t2 - 5t2x            = x2 - 5x + 6and y2 =  f2x = 2x2tdt            = t20x = x2For point of intersection, x2 - 5x + 6 = x2              x = 65and   y = x2 = 652 = 3625Therefore, the point of intersection is 65, 3625


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557.

The value of limnr = 1n1nern is

  • e

  • e - 1

  • 1 - e

  • 1 + e


558.

022 + x2 - xdx is equal to

  • π + 2

  • π + 32

  • π + 1

  • None of these


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559.

exsinexdx is equal to

  • - cosex + c

  • cosex + c

  • - cscex + c

  • None of these


560.

ex1x - 1x2dx is equal to

  • - exx2 + c

  • exx2 + c

  • exx + c

  • - exx + c


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