Correct value of ∫0πsin4xdx is from Mathematics

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 Multiple Choice QuestionsMultiple Choice Questions

561.

1 - x1 + xdx is equal to

  • cos-1x + 1 - xx - 2 + c

  • cos-1x - 1 - xx - 2 + c

  • cos-1x + 1 - xx + 2 + c

  • None of the above


562.

logx + 1 + x21 + x2dx is equal to

  • 12logx + 1 + x22 + c

  • logx + 1 + x22 + c

  • logx + 1 + x2 + c

  • None of the above


563.

sin8x - cos8x1 - 2sin2xcos2xdx is equal to

  • sin2x + c

  • - 12sin2x + c

  • 12sin2x + c

  • - sin2x + c


564.

dxsinx + sin2x is equal to

  • 16log1 - cosx + 12loglog1 + cosx - 23log1 + 2cosx + c

  • 6log1 - cosx + 2loglog1 + cosx - 23log1 + 2cosx + c

  • 6log1 - cosx + 12loglog1 + cosx + 23log1 + 2cosx + c

  • None of the above


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565.

fxg''x - f''xgxdx is equal to

  • fxg'x

  • f'(x)g(x) - f(x)g'(x)

  • f(x)g'(x) - f'(x)g(x)

  • f(x)g'(x) + f'(x)g(x)


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566.

Correct value of 0πsin4xdx is

  • 8π3

  • 2π3

  • 4π3

  • 3π8


D.

3π8

0πsin4xdx= 20π2sin4xdx= 2 × 3 × 14 × 2 × π2= 3π8  0π2sinnxdx = n - 1n - 3 ...nn - 2 ... . π2, if n is evenn - 1n - 3 ...nn - 2 ... . 1, if n is odd


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567.

0π2logsinxdx is equal to

  • - π2log2

  • πlog12

  • - π2log12

  • log2


568.

0πcos3xdx is equal to

  • - 1

  • 0

  • 1π

  • 1


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569.

Suppose f is such that f(- x) = - f(x), for every x and 01fxdx = 5, then - 10ftdt is equal to

  • 10

  • 5

  • 0

  • - 5


570.

Withthehelp of Trapezoidal rule fornumerical integration and the following table
x 0 0.25 0.50 0.75 1
f(x) 0 0.625 0.2500 0.5625 1

the value of 01fxdx is

  • 0.35342

  • 0.34375

  • 0.34457

  • 0.33334


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