The value of ∫01xdx by Trapezoidal rule taking x = 4 is

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591.

The value of 01xdx by Trapezoidal rule taking x = 4 is

  • 0.34375

  • 0.5

  • 0.38387

  • 0.353367


B.

0.5

Given integral is 01xdx

Suppose, we divided this into four equal intervals.

i 0 1 2 3 4
xi 0 0.25 0.5 0.75 1
yi 0 0.25 0.5 0.75 1

 By Trapezoidal rule01dx = h2y0 + 2y1 + y2 + y3 + y4          = 1 - 02 × 40 + 20.25 + 0.5 + 0.75 + 1         = 1821.5 + 1         = 183 + 1 = 12


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592.

dxx4 - 1 is equal to

  • 14logx - 1x + 1 - 12tan-1x + C

  • logx - 1x + 1 + C

  • 14logx - 1x + 1 + 12tan-1x + C

  • logx - 1x + 1 - 12tan-1x + C


593.

If e= 1, e1 = 2.72, e2 = 7.39, e3 = 20.09, e4 = 54.60, then the value of 04exdx using Simpson's rule, will be

  • 5.387

  • 53.87

  • 52.78

  • 53.17


594.

- 12x3 - xdx is equal to

  • 11

  • 4

  • 114

  • 411


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595.

According to Simpson's rule, the value of 17dxx is

  • 1.358

  • 1.958

  • 1.625

  • 1.458


596.

If sin2tan-11 - x1 + xdx = Asin-1x + Bx1 - x2 + C, then A + B is equal to

  • 10

  • 12

  • 1

  • - 12


597.

1e1logxdx is equal to

  • 1e

  • e

  • 21 - 1e

  • None of the above


598.

limx00x2sintdtx3 is equal to

  • 23

  • 13

  • 0


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599.

By trapezoidal rule, the approximate value of the integral 06dx1 + x2 is

  • 1.3128

  • 1.4108

  • 1.4218

  • None of these


600.

The value of the integral I = tanx + cotxdx, where x  0, π2, is

  • 2sin-1cosx - sinx + C

  • 2sin-1sinx - cosx + C

  • 2sin-1cosx + sinx + C

  • - 2sin-1sinx + cosx + C


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