∫exx2 + 1x + 12dx is equal to from

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691.

For any integer n  2, let Intann(x)dx. If  In = 1atann - 1x - bIn - 2 for n 2, then the ordered par (a, b) equals to

  • n - 1,  n - 1n - 2

  • n - 1,  n - 2n - 1

  • (n, 1)

  • (n - 1, 1)


692.

If x2 - 1x + 12xx2 + x+1dx= Atan-1x2 + x +1x C, in which C is a constant, then A =?

  • 12

  • 3

  • 2

  • 1


693.

By the defination of the definite integral, the value oflimn1415 +n5 + 2425 + n5 + 3435 + n6 + ... + n4n5 + n5 is

  • log2

  • 15log2

  • 14log2

  • 13log2


694.

0π6cos43θ . sin26θ = ?

  • π96

  • 5192

  • 5π256

  • 5π192


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695.

dxx - 1x2 - 1 is equal to

  • - x - 1x + 1 + C

  • x - 1x2 + 1 + C

  • - x + 1x - 1 + C

  • x2 + 1x - 1 + C


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696.

exx2 + 1x + 12dx is equal to

  • exx + 1 + C

  • - exx + 1 + C

  • exx - 1x + 1 + C

  • exx + 1x - 1 + C


C.

exx - 1x + 1 + C

Let I = exx2 + 1x + 12dx        = exx2 - 1 + 2x + 12dx        = exx2 - 1x + 12 + 2x + 12dx        = exx - 1x + 1 + 2x + 12dxLet fx = x - 1x+ 1 f'x = 1x + 1 - x - 11x + 12             = 2x + 12      I = exx - 1x + 1 + C            exfx + f'xdx = exfx + C


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697.

x + 1x1 + xexdx is equal to

  • log1 + xexxex + C

  • logxex1 + xex + C

  • logxex1 + xex + C

  • log1 + xex + C


698.

fxg'x - f'xgxfxgxloggx - logfxdx is equal to

  • loggxfx + C

  • 12loggxfx2 + C

  • gxfxloggxfx + C

  • loggxfx - gxfx + C


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699.

0π4sinx + cosx3 + sin2xdx = ? 

  • 12log3

  • log2

  • log(3)

  • 14log3


700.

- 111 + x + x2 - 1 - x + x21 + x + x2 + 1 - x + x2dx = ?

  • 3π2

  • π2

  • 0

  • - 1


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