Let fx = ∫x1 + x2dx x ≥

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 Multiple Choice QuestionsShort Answer Type

721.

Let S be the set of all integer solutions, (x, y, z), of the system of equationsx  2y + 5z = 0 2x + 4y + z = 0 7x + 14y + 9z = 0Such that  15 < x2 + y2 + z2 < 150. Then, the number of elements in the set S is equal to.


 Multiple Choice QuestionsMultiple Choice Questions

722.

Let fx = x - 2 and gx = ffx, x  0, 4. Then03gx - fxdx = ?

  • 0

  • 12

  • 32

  • 1


723.

The integral xxsinx + cosx2dx = ? Where Cis a constant of integration : 

  • tanx + xsecxxsinx + cosx + C

  • tanx - xsecxxsinx + cosx + C

  • secx + xtanxxsinx + cosx + C

  • secx - xsecxxsinx + cosx + C


724.

Let [t] denote the greatest integer  t. Then the equation in x, [x]2 + 2[x + 2] – 7 = 0 has :

  • no integral solution

  • infinitely many solutions

  • exactly two solutions

  • exactly four integral solutions


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725.

Let fx = x1 + x2dx x  0. Then f3 - f1 = ?

  • - π6 + 12 + 34

  • - π12 + 12 + 34

  • π12 + 12 - 34

  • π6 + 12 - 34


C.

π12 + 12 - 34

fx = x1 + x2dxLet x = tan2θdx = 2tanθsec2θfx = tanθ1 + tan2θ .  2tanθsec2θfx = tanθsec4θ .  2tanθsec2θfx = 2tan2θ . cos2θfx = 2sin2θfx = 1 - cos2θfx = θ - sin2θ2 =C= θ - tanθ1 + tan2θ + Cfx = tan-1x - x1 + x +Cnow f3 - f1 = tan-13 - 31 + 3 - tan-11 + 11 + 1= π3 - π4 + 12 - 34= π12 + 12 - 34


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726.

Let f be the twice differential function on 1, 6. If f2 = 8, f'2 = 5,f'x  1 and f''x  4, for all x  1, 6, then :

  • f5 + f'5  28

  • f'5 + f''5  20

  • f5  10

  • f5 + f'5  26


 Multiple Choice QuestionsShort Answer Type

727.

If the system of equations

x – 2y + 3z = 9

2x + y + z = b

x – 7y + az = 24,

has infinitely many solutions, then a – b is equal to :


 Multiple Choice QuestionsMultiple Choice Questions

728.

The integral π6π3tan3x . sin23x2sec2xsin23x + 3tanxsin6xdx = ?

  • - 19

  • 92

  • - 118

  • 718


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 Multiple Choice QuestionsShort Answer Type

729.

Let {x} and [x] denote the fractional part of x and the greatest integer r  x respectively of a real number x. if 0nxdx and 10(n2  n), (n  N, n > 1) are three consecutive terms of a G.P. then n is equal to ......


730.

If a = 2i^ + j^ + 2k^, then the value of i^ × a × i^2 + j^a × j^2 + k^ × a × k^2 = ?


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