Let  where .Then, a value of y is from Mathematics Inverse T

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 Multiple Choice QuestionsMultiple Choice Questions

1.

In ABC if θ is any angle, then bcosC + θ + ccosB - θ = ?

  • acotθ

  • acosθ

  • atanθ

  • asinθ


2.

The number of solutions of the trigonometric equation 1 + cosx . cos5x = sin2x in [0, 2π] is

  • 8

  • 12

  • 10

  • 6


3.

A value of θ for which fraction numerator 2 space plus space 3 straight i space sin space straight theta over denominator 1 minus 2 straight i space sin space straight theta end fraction is purely imaginary is

  • π/3

  • π/6

  • sin to the power of negative 1 end exponent open parentheses fraction numerator square root of 3 over denominator 4 end fraction close parentheses
  • sin to the power of negative 1 end exponent open parentheses fraction numerator square root of 3 over denominator 4 end fraction close parentheses
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4.

Consider f(x) = tan-1 open parentheses square root of fraction numerator 1 space plus sin space straight x over denominator 1 minus sin space straight x end fraction end root close parentheses comma space straight x space element of space open parentheses 0 comma space straight pi over 2 close parentheses. A normal to y = f (x) at x = π/6 also passes through the point

  • (0,0)

  • (0, 2π/3)

  • (π/6 ,0)

  • (π/6 ,0)

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5.

If 0≤x<2π, then the number of real values of x, which satisfy the equation cosx+cos2x+cos3x+cos4x=0, is :

  • 3

  • 5

  • 7

  • 7

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6. straight l im with straight x rightwards arrow 0 below space fraction numerator left parenthesis 1 minus cos 2 straight x right parenthesis left parenthesis 3 space plus cos space straight x right parenthesis over denominator straight x space tan space 4 straight x end fraction space is equal to 
  • 4

  • 3

  • 2

  • 2

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7.

Let tan to the power of negative 1 end exponent space straight y space equals tan to the power of negative 1 end exponent space straight x space plus space tan to the power of negative 1 end exponent space open parentheses fraction numerator 2 straight x over denominator 1 minus straight x squared end fraction close parentheses comma where vertical line straight x vertical line space less than space fraction numerator 1 over denominator square root of 3 space end fraction space.Then, a value of y is

  • fraction numerator 3 straight x squared minus straight x squared over denominator 1 minus 3 straight x squared end fraction
  • fraction numerator 3 straight x space plus space straight x cubed over denominator 1 minus 3 straight x squared end fraction
  • fraction numerator 3 straight x minus straight x cubed over denominator 1 plus 3 straight x squared end fraction
  • fraction numerator 3 straight x minus straight x cubed over denominator 1 plus 3 straight x squared end fraction


A.

fraction numerator 3 straight x squared minus straight x squared over denominator 1 minus 3 straight x squared end fraction
vertical line straight x vertical line less than space fraction numerator 1 over denominator square root of 3 end fraction space rightwards double arrow negative fraction numerator 1 over denominator square root of 3 end fraction less than straight x space less than thin space fraction numerator 1 over denominator square root of 3 end fraction
Let space straight x space equals space tan space straight theta
rightwards double arrow fraction numerator negative straight pi over denominator 6 end fraction space less than space straight theta space less than thin space straight pi over 6
tan to the power of negative 1 end exponent space straight y space equals space straight theta space plus space tan to the power of negative 1 end exponent space left parenthesis tan space 2 straight theta right parenthesis
space equals space straight theta space plus space 2 straight theta space equals space 3 straight theta
rightwards double arrow space straight y space equals space tan space 3 straight theta
straight y equals space fraction numerator 3 space tan space straight theta minus tan cubed space straight theta over denominator 1 minus 3 space tan squared straight theta end fraction
straight y space equals space fraction numerator 3 straight x minus straight x cubed over denominator 1 minus 3 straight x squared end fraction
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8.

If y  = sec (tan-1 x), then dy/dx at x = 1 is equal to 

  • fraction numerator 1 over denominator square root of 2 end fraction
  • 1 half
  • 1

  • 1

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9.

If A = sin2 x + cos4 x, then for all real x

  • 3/4 ≤ A ≤ 1

  • 31/16 ≤ A ≤ 1

  • 1≤ A ≤2

  • 1≤ A ≤2

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10.

If cos-1 x - cos-1 y/2 = α, then 4x2 − 4xy cos α + y2 is equal to

  • 2 sin 2α

  • 4

  • 4 sin2 α

  • 4 sin2 α

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