If cos-1x2 - y2x2 + y2 = k a constant, then dydx = ?
yx
xy
x2y2
y2x2
A.
Given, cos-1x2 - y2x2 + y2 = kx2 - y2x2 + y2 = coskOn differentiating w.r.t. x, we getx2 + y22x - 2ydydx - x2 - y22x + 2ydydx x2 + y22 = 0⇒ - 4x2ydydx + 4xy2 = 0⇒ dydx = yx