If A = 827125235111, then the value of A2 is equal to
0
36
64
3600
The roots of the equation x - 1111x - 1111x - 1 = 0 are
1, 2
- 1, 2
- 1, - 2
1, - 2
B.
We have,x - 1111x - 1111x - 1 = 0On applying C1 → C1 + C2 + C3 , we get x + 111x + 1x - 11x + 11x - 1 = 0On taking (x + 1) common from C1, we get x + 11111x - 1111x - 1 = 0On applying, R1 → R1 - R2, R2 → R2 - R3, we getx + 102 - x00x - 22 - x11x - 1 = 0⇒ x + 1 . 2 - x2 - 0 = 0⇒ x + 12 - x2 = 0⇒ x = - 1, 2
111pqrpqr + 1 is equal to
q - p
q + p
q
p
Let A = 5010 and B = 205- 10. If 4A + 5B - C = 0, then C is
525- 10
205- 10
5- 1025
12025- 10
If U = 12- 121212, then U-1 is
UT
U
I
If A = 0- 1010000- 1, then A-1 is
AT
A2
A
If x + yx - y2x + zx + z = 0011, then the values of x, y and z are respectively
0, 0, 1
1, 1, 0
- 1, 0, 0
0, 0, 0
715800231 + 510 is equal to
1627
2716
1516
1615
If 12413514a is singular, then the value of a is
a = - 6
a = 5
a = - 5
a = 6
If 12- 3045001xyz = 111, then (x, y, z) is equal to
(1, 6, 6)
(1, - 6, 1)
(1, 1, 6)
(6, - 1, 1)