The letters of the word COCHIN are permuted and all permutations

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 Multiple Choice QuestionsMultiple Choice Questions

11.

The number of ways in which the letters of the word ARRANGE can be permuted such that the R's occur together, is

  • 7!2! 2!

  • 7!2!

  • 6!2!

  • 5! × 2!


12.

If 1Cr5 + 1Cr6 = 1Cr4, then the value of r is

  • 4

  • 2

  • 5

  • 3


13.

If A = 5n - 4n - 1: n  N and B = 16n - 1: n  N, then

  • A = B

  • A  B = φ

  • A  B

  • B A


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14.

The letters of the word COCHIN are permuted and all permutations are arranged in an alphabetical order as in an English dictionary. The number of words that appear before the word COCHIN is

  • 96

  • 48

  • 183

  • 267


A.

96

In a dictionary, the words at each stage are arranged in alphabetical order.

In the given problem, we must consider the words beginning with C, C, H, I, N, 0 in order. So,

Total number of words starting with C=5!=120, which include the word COCHIN also.

 The number of words that appear before the word COCHIN is less than 120.

Now, Number of words starting with CC = 4!

Number of words starting with CH = 4!

Number of words starting with CI = 4!

Number of words starting with CN = 4!

Next word starting with CO i.e. COCHIN = 1

  Required number of words = 4 x 4! = 96


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15.

The letters of the word 'COCHIN' are permuted and all the permutations are arranged in alphabetical order as in English dictionary. The number of words that appear before the word 'COCHIN', is

  • 360

  • 192

  • 96

  • 48


16.

The number of digits in 20301 given, log102 = 0.3010 is

  • 602

  • 301

  • 392

  • 391


17.

The number of solutions of the equation x + y + z = 10 where x, y and z are positive integers

  • 36

  • 55

  • 72

  • 45


18.

Let n be a positive even integer. If the ratio of the largest coefficient and the 2nd largest coefficient in the expansion of (1 + x)n is 11 : 10. Then, the number of terms in the expansion of (1 + x)n is

  • 20

  • 21

  • 10

  • 11


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19.

There are 100 students in a class. In an examination, 50 of them failed in Mathematics, 45 failed in Physics, 40 failed in Biology and 32 failed in exactly two of the three subjects. Only one student passed in all the subjects. Then, the number of students failing in all the three subjects

  • is 12

  • is 4

  • is 2

  • cannot be determined from the given information


20.

Four speakers will address a meeting where speaker Q will always speak P. Then, the number of ways in which the order of speakers can be prepared is

  • 256

  • 128

  • 24

  • 12


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