If PA = 112, PB = 512 and 

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 Multiple Choice QuestionsMultiple Choice Questions

41.

A box contains 9 tickets numbered 1 to 9 inclusive. If 3 tickets are drawn from the box one at a time, the probability that they are alternatively either {odd, even, odd} or {even, odd, even}is:

  • 517

  • 417

  • 516

  • 518


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42.

If PA = 112, PB = 512 and PBA = 115, then P(A B) is equal to :

  • 89180

  • 90180

  • 91180

  • 92180


A.

89180

 PA = 112, PB = 512 and PBA = 115We know that  PBA = PA  BPA  115 = PA  B115     PA  B = 1180Also, PA  B = PA + PB - PA  B                        = 112 + 512 - 1180                        = 15 + 75 - 1180 = 89180


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43.

A bag contains 3 black and 4 white balls. Two balls are drawn one by one at random without replacement. The probability that the second drawn ball is white, is

  • 449

  • 17

  • 47

  • 1249


44.

A coin is tossed 4 times. The probability that atleast one head turns up 1s

  • 116

  • 216

  • 1416

  • 1516


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45.

A speaks truth in 75% cases and B speaks truth in 80% cases, The probability that they contradict each other in a statement, is

  • 720

  • 1320

  • 35

  • 25


46.

The probability that a leap year will have 53 Friday or 53 Saturday, is

  • 27

  • 37

  • 47

  • 17


47.

Ten coins are thrown simultaneously, the probability of getting atleast 7 heads is

  • 63256

  • 121172

  • 113512

  • 1164


48.

If four digits are taken fromthe digits 1, 2, 3, 4, 5, 6, 7. The probability that the sum of digits is less than 12, is

  • 335

  • 435

  • 235

  • 135


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49.

The probability of happening exactly one of the two events A and B is

  • PA + PB - 2PA  B

  • PA + PB - PA  B

  • P(A) - P(B)

  • None of the above


50.

In a throw of two dice, the probability of getting a sum of 7 or 11 is

  • 29

  • 79

  • 59

  • None of these


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