Let X and Y be two events such that P(X/Y) = 1/2, P(Y/X) = 1/3 and P(X ∩ Y) = 1/6. Which of the following is incorrect?
P(X Y) = 2/3
X and Y are independent
P(XC ∩ Y) = 2/3
X and Y are not independent
If n integers taken at random are multiplied together, then the probability that the last digit of the product is 1, 3, 7 or 9 is
4 -
None
B.
In any number, the last digits can be 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. Therefore, the last digit of each number can be chosen in 10 ways. Thus, the exhaustive number of ways in 10°. If the last digit be 1, 3, 7 or 9, then none of the numbers can be even or end in 0 or 5.
Thus, we have a choice of 4 digits viz. 1, 3, 7 or 9 with which each of n numbers should end. So, favourable number of ways is 4n.
Hence, required probability =
A bag contains (n + 1) coins. It is known that one of these coins shows heads on both sides, whereas the other coins are fair. One coin is selected at random and tossed. If the probability that toss results in heads is , then the value of n is
5
4
3
None of these
If A and B are two given events, then P(A ∩ B) is
equal to P(A) + P(B)
equal to P(A) + P(B) + P(A B)
not less than P(A) + P(B) - 1
not greater than P(A) + P(B) - P(A B)
From a city population, the probability of selecting a male or smoker , a male smoker is and a male, if a smoker is already, selected, is Then, the probability of
selecting a male is
selecting a smoker is
selecting a non-smoker is
selecting a smoker, if a male is first selected, is given by
The probability of atleast one double six being thrown in n throws with two ordinary dice is greater than 99%.
Then, the least numerical value of n is
100
164
170
184
If the integers m and n are chosen at random from 1 to 100, then the probability that a number of the form 7n + 7m is divisible by 5, equals to
Let X denote the sum of the numbers obtained when two fair dice are rolled. The variance and standard deviation of X are
If two events A and B. If odds against A are 2 : 1 and those infavour of A B areas 3 : 1, then
None of these