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 Multiple Choice QuestionsMultiple Choice Questions

151.

Let X and Y be two events such that P(X/Y) = 1/2, P(Y/X) = 1/3 and P(X ∩ Y) = 1/6. Which of the following is incorrect?

  • P(X  Y) = 2/3

  • X and Y are independent

  • P(XC ∩ Y) = 2/3

  • X and Y are not independent


152.

If n integers taken at random are multiplied together, then the probability that the last digit of the product is 1, 3, 7 or 9 is

  • 4n5n

  • 2n5n

  • 4 - 2n5n

  • None


153.

A bag contains (n + 1) coins. It is known that one of these coins shows heads on both sides, whereas the other coins are fair. One coin is selected at random and tossed. If the probability that toss results in heads is 712, then the value of n is

  • 5

  • 4

  • 3

  • None of these


154.

If A and B are two given events, then P(A ∩ B) is

  • equal to P(A) + P(B)

  • equal to P(A) + P(B) + P(A  B)

  • not less than P(A) + P(B) - 1

  • not greater than P(A) + P(B) - P(A  B)


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155.

From a city population, the probability of selecting a male or smoker 710, a male smoker is 25 and a male, if a smoker is already, selected, is 23 Then, the probability of

  • selecting a male is 32

  • selecting a smoker is 15

  • selecting a non-smoker is 25

  • selecting a smoker, if a male is first selected, is given by 85


156.

If A, B, C are three events associated with a random experiment, then PAPBAPCA  B

  • PA  B  C

  • PA B C

  • PCA  B

  • PBA


157.

The probability of atleast one double six being thrown in n throws with two ordinary dice is greater than 99%.

Then, the least numerical value of n is

  • 100

  • 164

  • 170

  • 184


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158.

If the integers m and n are chosen at random from 1 to 100, then the probability that a number of the form 7n + 7m is divisible by 5, equals to

  • 14

  • 12

  • 18

  • 13


A.

14

Let l = 7n + 7m, then we observe that 71, 72, 7and 74 ends in 7, 9, 3 and 1, respectively. Thus, tends in 7, 9, 3 or 1 according as i is of the form 4K + 1, 4K + 2, 4K - 1 or 4K, respectively.

If S is the sample space, then n(S) = (100)2. 7m + 7n is divisible by 5, if

(i) m is of the form 4K + 1 and n is of the form 4K - 1 or

(ii) m is of the form 4K + 2 and n is of the form 4K or

(iii) m is of the form 4K - 1 and n is of the form 4K + 1 or

(iv) m is of the form 4K and n is of the form 4K + 1.

Thus, number of favourable ordered pairs (m, n) = 4 × 25 × 25.

Hence, required probability = 4 × 25 × 251002 = 14


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159.

Let X denote the sum of the numbers obtained when two fair dice are rolled. The variance and standard deviation of X are

  • 316 and 316

  • 356 and 356

  • 176 and 176

  • 316 and 356


160.

If two events A and B. If odds against A are 2 : 1 and those infavour of A  B areas 3 : 1, then

  • 12  PB  34

  • 512  PB  34

  • 14  PB  35

  • None of these


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