A random variable X has the probability distribution x 1 2 3 4

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 Multiple Choice QuestionsMultiple Choice Questions

191.

A parents has two children. If one of them is boy, then the probability that other is, also a boy, is

  • 1/2

  • 1/4

  • 1/3

  • None of these


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192.

A random variable X has the probability distribution
x 1 2 3 4 5 6 7 8
P(x) 0.15 0.23 0.12 .010 0.20 0.08 0.07 0.05

For the events E = {x is prime number} and F = {x < 4} the probability of P(E ∪ F) is

  • 0.50

  • 0.77

  • 0.35

  • 0.87


B.

0.77

Given, E = {x is a prime number}

P(E) = P(2) + P(3) + P(5) + P(7)

       = 0.23 + 0.12 + 0.20 + 0.07 = 0.62

and F = {x < 4}

  P(F) = P(1) + P(2) + P(3)

         = 0.15 + 0.23 + 0.12 = 0.50

and P(E  F) = P(2) + P(3)

                    = 0.23 + 0.12 = 0.35

 PE  F = PE +PF - PE  F

                 = 0.62 + 0.50- 0.35

                 = 0.77


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193.

From a group of 8 boys and 3 girls, a commitee of 5 members to be formed. Find the probability that 2 particular girls are included in the committe is

  • 411

  • 211

  • 611

  • 811


194.

A four digit number is to be formed using the digits 1, 2, 3 4, 5 6, 7 (no digit is being repeated in any number). Then, the probability that it is > 4000, is

  • 3/2

  • 1/2

  • 4/7

  • 3/7


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195.

If x follows the Binomial distribution with parameters n = 6 and p and 9P(X = 4) = P(X = 2), then p is

  • 1/4

  • 1/3

  • 1/2

  • 2/3


196.

One card is drawn at random from a pack of playing cards the probability that it is an ace or black king or the queen of the heart will be

  • 352

  • 752

  • 652

  • 152


197.

15 coins are tossed, then the probability of getting 10 heads will be

  • 51132768

  • 100132768

  • 300332768

  • 300532768


198.

The odds against solving a problem by A and B are 3 : 2 and 2 : 1 respectively, then the probability that the problem will be solved, is

  • 35

  • 215

  • 25

  • 1115


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199.

If random variable waiting time in minutes for bus and probability density function of x is given by

fx = 15, 0  x  50  , otherwise

then probability of waiting time not more than 4 minutes is equal to

  • 0.3

  • 0.8

  • 0.2

  • 0.5


200.

If the probability density function of a random variable X is given as
xi - 2 - 1 0 1 2
P(X = xi) 0.2 0.3 0.15 0.25 0.1

then F(0) is equal to

  • P(X < 0)

  • P(X > 0)

  • 1 - P(X > 0)

  • 1 - P(X < 0)


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