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 Multiple Choice QuestionsMultiple Choice Questions

201.

If random variable X ~ Bn = 5, P = 13, then P(2 < X < 4) is equal to

  • 80243

  • 40243

  • 40343

  • 80343


202.

At random variable X ~ B(n, p), if values of mean and variance of X are 18 and 12 respectively, then total number of possible values of X are

  • 54

  • 55

  • 12

  • 18


203.

Probability that a person will develop immunity after vaccinations is 0.8. If 8 people are given the vaccine, then probability that all develop immunity is =

  • (0.2)8

  • (0.8)8

  • 1

  • C680.260.82


204.

For the following distribution function F(x) of a rv.X.

x 1 2 3 4 5 6
F(x) 0.2 0.37 0.48 0.62 0.85 1

P3 < x  5 =

  • 0.48

  • 0.37

  • 0.27

  • 1.47


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205.

Probability of solving a particular question by person A is 1/3 and probability ofsolving that question by person B is 2/5. what is the probability of solving that question by atleast one of them ?

  • 35

  • 79

  • 25

  • 23


206.

The probabilities that Mr. A and Mr. B will die within a year are 12 and 13 respectively, then the probability that only one of them will be alive at the end of the year, is

  • 56

  • 12

  • 23

  • None of the above


207.

The probability that a man will live 10 more years, is 14 and the probability that his wife  will live 10 more years, is 13. Then, what is the probability that neither will be alive in 10 yr ?

  • 12

  • 37

  • 23

  • 14


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208.

The probability that in a year of the 22nd century chosen at random, there will be 53 Sunday, is

  • 328

  • 228

  • 728

  • 528


D.

528

We know, a leap year is fallen within 4 yr, so its probability = 25100 = 14

In a century, the probability of 53 Sunday in a leap year = 14 × 27 = 228

Non-leap year in a century = 75

Probability of selecting a non-leap year

= 75100 = 34

Probability of 53 Sunday in a non-leap year = 17

Similarly, in a century, probabilities of 53 Sunday in a non-leap year = 34 × 17 = 328

 Required probability= 228 + 328 = 528


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209.

If P(A) = 65, P(B) = 80, then P(A  B) lies in the interval

  • [30, 80]

  • [35, 75]

  • [4, 70]

  • [0.45, 0.65]


210.

For any two independent events E1 and E2 in a space S, PE1  E2  E1  E2 is equal to

  •  14

  • > 14

  •  12

  • > 12


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