A function is matched below against an interval where it is supposed to be increasing. Which of the following pairs is incorrectly matched?
Interval | Function |
(-∞, ∞) | x3 – 3x2 + 3x + 3 |
Interval | Function |
[2, ∞) | 2x3 – 3x2 – 12x + 6 |
Interval | Function |
(-∞, 1/3] | 3x2 – 2x + 1 |
Interval | Function |
(-∞, 1/3] | 3x2 – 2x + 1 |
A real valued function f(x) satisfies the functional equation f(x – y) = f(x) f(y) – f(a – x) f(a + y) where a is a given constant and f(0) = 1, f(2a – x) is equal to
–f(x)
f(x)
f(a) + f(a – x)
f(a) + f(a – x)
Let R = {(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)} be a relation on the set A = {1, 2, 3, 4}. The relation R is
a function
reflexive
not symmetric
not symmetric
C.
not symmetric
Let R = {(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)} is a relation on the set A = {1, 2, 3, 4}, then
(a) Since ∈ R and (2,3) ∈ R, so R is not a function.
(b) Since (1, 3) ∈ R and (3, 1) ∈ R but (1, 1) ∉ R. So R is not transitive.
(c) Since (2, 3) ∈ R but (3, 2) ∉ R, so R is not symmetric.
(d) Since (4, 4) ∉ R so R is not reflexive,
The range of the function 7-xPx-3 is
{1, 2, 3}
{1, 2, 3, 4, 5}
{1, 2, 3, 4}
{1, 2, 3, 4}
Let f and g be differentiable functions satisfying g′(a) = 2, g(a) = b and fog = I (identity function). Then f ′(b) is equal to
1/2
2
2/3
2/3
Let S = {t ∈ R: f(x) = |x-π|.(e|x| - 1) sin |x| is not differentiable at t}. Then the set S is equal to
{0,π}
{0}
{π}
Let S = { x ∈ R : x ≥ 0 and Then S:
Contains exactly four elements
Is an empty set
Contains exactly one element
Contains exactly two elements
On the set R of real numbers we define xPy if and only if . Then, the relation P is
reflexive but not symmetric
symmetric but not reflexive
transitive but not reflexive
reflexive and symmetric but not transitive
On R, the relation p be defined by 'xy holds if and only if x- y is zero or irrational'. Then,
s reflexive and transitive but not symmetric
s reflexive and symmetric but not transitive
s symmetric and transitive but not reflexive
is equivalence relation