Suppose four distinct positive numbers a1, a2, a3, a4 are in G.P. Let b1 = a1, b2 = b1 + a2, b3 = b2 + a3 and b4 = b3 + a4.
Statement-I: The numbers b1, b2, b3, b4are neither in A.P. nor in G.P. Statement-II: The numbers b1, b2, b3, b4 are in H.P.
Both statement-I and statement-II are true but statement-II is not the correct explanation of statement-I
Both statement-I and statement-II are true, and statement-II is correct explanation of Statement-I
Statement-I is true but statement-II is false.
Statement-I is true but statement-II is false.
Let a1, a2, a3, ...., a49 be in A.P. such that
33
66
68
34
D.
34
Let a1 = a and common difference = d
Given, a1 + a5 + a9 + ..... + a49 = 416
= a + 24d = 32 ...(i)
Also, a9 + a43 = 66
= a + 25d = 33 ...(ii)
Solving (i) & (ii),
We get d = 1, a = 8
Let f : R ➔ R be such that f is injective and f(x)f(y) = f(x + y) for x, y R. If f(x), f(y), f(z) are in G.P., then x, y, z are in
AP always
GP always
AP depending on the value of x, y, z
GP depending on the value of x, y, z
In a GP series consisting of positive terms, each term is equal to the sum of next two terms. Then, the common ratio of this GP series is