If ax = by = cz = du and a, b, c, d are in GP, then x, y, z,

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

121.

Let a, b and c be in AP and a < 1, b < 1, c < 1. If x = 1 + a + a2 + ... to , y = 1 + b + b2 + ... to , z = 1 + c + c2 + ... to , then x, y and z are in

  • AP

  • GP

  • HP

  • None of these


122.

The sum of the series

1 + 12 + 222! + 12 + 22 + 323! + 12 + 22 + 32 + 424! + ... is

  • 3e

  • 176e

  • 136e

  • 196e


123.

For a GP, an = 3(2n), ∀ n ∈ N. Find the common ratio

  • 2

  • 1/2

  • 3

  • 1/3


124.

If a, b, c are in HP, then ab + c, bc + a, ca + b will be in

  • AP

  • GP

  • HP

  • None of these


Advertisement
125.

The sum of the coefficients of (6a - 5b)n, where n is a positive integer, is

  • 1

  • - 1

  • 2n

  • 2n - 1


Advertisement

126.

If ax = by = cz = du and a, b, c, d are in GP, then x, y, z, u are in

  • AP

  • GP

  • HP

  • None of these


C.

HP

We have,

ax = by = cz = du

Let ax = by = cz = du = k

 a = k1x, b = k1y, c = k1z, d = k1u       ...(i)

Since, a, b, c, d are in GP.

     ba = cb = dc k1yk1x = k1zk1y = k1uk1z           using Eq. (i) k1y - 1x = k1z - 1y = k1u - 1z 1y - 1x = 1z - 1y = 1u - 1z x, y, z, u are in AP. x, y, z, u are in HP.


Advertisement
127.

If x is numerically so small so that x2 and higher power of x can be neglected, then 1 + 2x332 . 32 + 5x- 15 is approximately equal to

  • 32 + 31x64

  • 31 + 32x64

  • 31 - 32x64

  • 1 - 2x64


128.

If the sides of a right angle triangle form an AP, the 'sin' of the acute angles are

  • 35, 45

  • 3, 13

  • 5 - 12, 5 - 12

  • 3 - 12, 3 - 12


Advertisement
129.

If H is the harmonic mean between P and Q, then the value of HP + HQ is

  • 2

  • PQP +Q

  • 12

  • P +QPQ


130.

The value of 23! + 45! + 67! + ...

  • e

  • 2e

  • e2

  • 1e


Advertisement