If the circle x2 + y2 + 8x - 4y + c = 0 touches the circle x2 + y

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 Multiple Choice QuestionsMultiple Choice Questions

161.

A pair of perpendicular lines passes through the origin and also through the points of intersection of the curve x2 + y2 = 4 with x + y = a, where a > 0. Then a is equal to

  • 2

  • 3

  • 4

  • 5


162.

If 3x2 - 11xy + 10y2 - 7x + 13y + k = 0 denotes a pair of straight lines, then the point of intersection of the lines is

  • (1, 3)

  • (3, 1)

  • (- 3, 1)

  • (1, - 3)


163.

The number of points P(x, y) with natural numbers as coordinates that lie inside the quadrilateral formed by the lines 2x + y = 2, x = 0, y = 0 and x + y = 5 is

  • 12

  • 10

  • 6

  • 4


164.

The image of the point (3, 8) in the line x + 3y = 7 is

  • (1, 4)

  • (4, 1)

  • (- 1, - 4)

  • (- 4, - 1)


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165.

The line joining the points A(2, 0) and B(3, 1) is rotated through an angle of 45°, about A in the anti-clockwise direction. The coordinates of B in the new position

  • 2, 2

  • 2, 2

  • (2, 2)

  • 2, 2


166.

If one of the lines in the pair of straight line given by 4x2 + 6xy + ky2 = 0 bisects the angle between the coordinate axes, then k ∈

  • {- 2, - 10}

  • {- 2, 10}

  • {- 10, 2}

  • {2, 10}


167.

If ax2 + 2hxy +by2 + 2gx + 2fy + c = 0represents a pair of parallel lines, theng2 - acf2 - bc, is equal to

  • ab

  • ab

  • ba

  • ba


168.

If s and p are respectively the sum and the product of the slopes of the lines 3x- 2xy - 15y2 = 0, then s: p is equal to

  • 4 : 3

  • 2 : 3

  • 3 : 5

  • 3 : 4


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169.

If the lines 3x + 4y - 14 = 0 and 6x + By + 7 = 0 are both tangents to a circle, then its radius is

  • 7

  • 72

  • 74

  • 76


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170.

If the circle x2 + y2 + 8x - 4y + c = 0 touches the circle x2 + y2 + 2x + 4y - 11 = 0 externally and cuts the circle x+y2 - 6x + By + k = 0 orthogonally, then k is equal to

  • 59

  • - 59 

  • 19

  • - 19 


B.

- 59 

Given that circle x2 + y2 + 8x - 4y + c = 0touches the circle x2 + y2 + 2x + 4y - 11 = 0then, C1C2 = r1 + r2   . . . iwhere C1 = - 4, 2r1 = 16 + 4 - c = 20 - cC2 = - 1, - 2and r2 = 1 + 4 + 11 = 4 From eq. i- 4 + 12 + 2 + 22= 20 - c + 4 5 = 20 - c + 4 c = 19Also, the circle x2 +y2 +8x - 4y +c = 0cuts the circles x2 + y2 - 6x + 8y + k = 0orthogonally, then c1 3, - 4C1C32 = r12 + r32Where r1 = 16 +4 - c r3 = 9 + 16 - k - 4 - 32 +2 + 42 = 20 - c + 25 - k 49 + 36 = 45 - k - c    k + c = - 40  k +19 = - 40           k = - 59


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