The equation of a straight line passing through the point (1, 2) and inclined at 45° to the line y = x + 1 is
5x + y = 7
3x + y = 5
x + y = 3
x - y + 1 = 0
A straight line is equally inclined to all the three coordinate axes. Then, an angle made by the line with the y-axis is
If p and q are the perpendicular distances from the origin to the straight lines xsec - ycosec( = and xcos() + ysin() = cos(2, then
4p2 + q2 = a2
p2 + q2 = a2
p2 + 2q2 = a2
4p2 + q2 = 2a2
If 2x + 3y =5 is the perpendicular bisector of the line segment joining the points A (1, 1/3) and B, then B is equal to
If the points (1, 2) and (3, 4) lie on the same side of the straight line 3x - 5y + a = 0, then a lies in the set
[7, 11]
R - [7, 11]
If the equation represents a pair of, straight lines, then the square of the distance of their point of intersection from the origin is
C.
The equation of a straight line; perpendicular to 8x - 4y = 6 and forming a triangle of area 6sq. units with coordinate axes, is
x - 2y = 6
4x + 3y = 12
4x + 3y + 24 = 0
3x + 4y = 12