Find the angle subtended by the double ordinate of length 2a of the parabola y2 = ax at its vertex.
The equation to the pairs of opposite sides of a parallelogram are x2 - 5x + 6 = 0 and y2 - 6y + 5. Find the equations its diagonals.
Opposite sides of a parallelogram are,
x2 - 5x + 6 = 0 ie, (x - 3) (r - 2) = 0
or x = 2, x = 3 ...(i)
and y2 - 6y + 5 = 0
i.e, (y - 1)(y - 5) = 0
or y = 1, y = 5 ...(ii)
The intersection lines of Eqs. (i) and (ii) are A(2, 1), B(3, 1), C(3, 5), D(2, 5).
Equation of diagonal AC is,
And equation of diagonal BD is,
The locus of a point P which moves such that 2PA = 3PB, where A(0, 0) and B(4,- 3) are points, is
5x2 - 5y2 - 72x + 54y + 225 = 0
5x2 + 5y2 - 72x + 54y + 225 = 0
5x2 + 5y2 + 72x - 54y + 225 = 0
5x2 + 5y2 - 72x - 54y - 225 = 0
The equation of the plane through the intersection of the planes x + y + z = 1 and 2x + 3y - z + 4 = 0 and parallel to X-axis, is
y - 3z + 6 = 0
3y - z + 6 = 0
y + 3z + 6 = 0
3y - 2z + 6 = 0
If the direction cosines of two lines are connected by the equations l + m + n = 0, l2 + m2 - n2 = 0, then the angle between the lines is
The equation of the plane which contains the origin and the line of intersection of the planes r · a = d1 and r · b = d2, is
r . (d1a + d2b) = 0
r . (d2a - d1b) = 0
r . (d2a + d1b) = 0
r . (d1a - d2b) = 0
If from a point P(a, b, c) perpendiculars PA and PB are drawn to YZ and ZX - planes, then the equation of the plane OAB is
bcx + cay + abz = 0
bcx + cay - abz = 0
- bcx + cay + abz = 0
bcx - cay + abz = 0
If (2, 7, 3) is one end of a diameter of the sphere x2 + y2 + z2 - 6x - 12y - 2z + 20 = 0, then the coordinates of the other end of the diameter are
(- 2, 5, - 1)
(4, 5, 1)
(2, - 5, 1)
(4, 5. - 1)