The point of intersection of the straight lines and is
(- 3, - 4, - 5)
(- 3, 4, 5)
(- 3, 4, - 5)
(3, - 4, 5)
The straight line is parallel to the plane . Then, the distance between the straight line and the plane is
B.
Clearly, given line passes through the point and is parallel to the given plane.
Distance between the line and the plane
= Length of perpendicular from to the given
plane
The equation of the plane that passes through the points (1, 0, 2), (-1, 1, 2), (5, 0, 3) is
x + 2y - 4z + 7 = 0
x + 2y - 3z + 7 = 0
x - 2y + 4z + 7 = 0
2y - 4z - 7 + x = 0
The equation of the plane passing through the intersection of the planes x + 2y + 3z + 4 = 0 and 4x + 3y + 2z + 1 = 0 and the origin is :
3x + 2y + z + 1 = 0
3x + 2y + z = 0
2x + 3y + z = 0
x + y + z = 0
The equation of the plane passing through (2, 3, 4) and parallel to the plane 5x - 6y + 7z = 3 is :
5x - 6y + 7z + 20 = 0
5x - 6y + 7z - 20 = 0
- 5x + 6y - 7z + 3 = 0
5x + 6y + 7z + 3 = 0