The inclination of the straight line passing through the point (- 3, 6) and the mid point of the line joining the points ( 4, - 5) and (- 2, 9) is:
A point moves such that the area of the triangle formed by it with the points (1, 5) and (3, - 7) is 21 sq unit Then locus of the point is :
6x + y - 32 = 0
6x - y + 32 = 0
x + 6y - 32 = 0
6x - y - 32 = 0
The line = 1 cuts the x-axis at P. The equation of the line through P perpendicular to the given line is :
x + y = ab
x + y = a + b
ax + by = a2
bx + ay = b2
The value of . for which the lines 3x + 4y = 5, 2x + 3y = 4and x + 4y = 6 meet at a point, is :
2
1
4
3
A.
2
The given lines are
3x + 4y = 5 ...(i)
2x + 3y = 4 ...(ii)
and x + 4y = 6 ...(iii)
on solving Eqs. (i) and (ii), we get
x = - 1 and y = 2
All lines meet at a point, therefore the above point satisfies the Eq. (iii)
Three vertices of a parallelogram taken in order are (- 1, - 6), (2, - 5) and (7, 2). The fourth vertex is :
(1, 4)
(1, 1)
(4, 4)
(4, 1)
If the equation 2x2 + 7 xy + 3y2 - 9 x - 7y + k = 0 represents a pair of lines, then k is equal to
4
2
1
- 4
Distance between the pair of lines represented by the equation x2 - 6xy + 9y2 + 3 - 9y - 4 = 0 is: