What are the DR's of vector parallel to (2, - 1, 1) and (3 4, - 1) ?
(1, 5, - 2)
(- 2, - 5, 2)
(- 1, 5, 2)
(- 1, - 5, - 2)
The symmetric equation of lines 3x + 2y + z - 5 = 0 and x + y - 2z - 3 = 0, is
C.
Let a, b, c be the direction ratios of required line.
3a + 2b + c = 0 and a + b - 2c = 0
In order to find a point on the required line we put z = 0 in the two given equations to obtain, 3x + 2y = 5 and x + y = 3 Solving these two equations, we get x = - 1, y = 4.
Coordinates of point on required line are (- 1, 4, 0).
Hence, required line is
The equation of the plane containing the line and the point (0, 7, - 7) is
x + y + z = 1
x + y + z = 2
x + y + z = 0
None of these
A point on XOZ - plane divides the join of (5, - 3, - 2) and (1, 2, - 2) at
(5, 0, 2)
(5, 0, - 2)
If the line makes angles , with the planes XOY, YOZ, ZOX respectively, then , is equal to
1
2
3
4